5. Write a C++ program to create a class called DATE. Accept two valid dates in the form dd/mm/yy. Implement the following operations by overloading the + and - operators. After every operation display the results by overloading the operator <<. i)no_of_days=d1-d2; where d1 and d2 are date objects, d1>=d2 and no_of_days is an integer. ii)d2=d1+no_of_days; where d1 is a DATE object and no_of_days is an integer

#include<iostream.h>

#include<process.h>  

class date

{

 private:     int mm,dd,yy;

 public:       void getdate();

                    int operator -(date);

                   date operator +(int);

};

void date::getdate()

{

     cout<<"enter a valid date(dd mm yy)\n";

     START

     cin>>dd>>mm>>yy;

     if((mm==2) && (dd>29))

{

 cout<<"wrong input!!!\n";

 cout<<"\n enter the date again....\n";

 goto START;

 }

 if((mm>12)||(dd>31))

 {

 cout<<"wrong input!!!\n";

 cout<<"\n enter the date again....\n";

 goto START;

}

 if((mm==4||mm==6||mm==9||mm==11) && (dd>30))

 {

 cout<<"wrong input!!!\n";

 cout<<"\nenter the date again....\n";

 goto START;

 }

 if((yy%4)!=0 && (mm==2) && (dd>28))

 {

 cout<<"wrong input!!!\n";

 cout<<"\nenter the date again....\n";

 goto START;

 }

}

// operator overloaded function to find the no. of days between two dates

int date::operator -(date d2)

{

 int i,nod1,nod2,nody,lc,no_of_days;

 nod1=nod2=lc=0;

  for(i=1;i<mm;i++)

 {

     if(i==1||i==3||i==5||i==7||i==8||i==10||i==12)

     nod1+=31;

     else if(i==2)

     nod1+=28;

     else

     nod1+=30;

 }

 nod1+=dd;

 for(i=1;i<d2.mm;i++)

 {

         if(i==1||i==3||i==5||i==7||i==8||i==10||i==12)

         nod2+=31;

        else if(i==2)

        nod2+=28;

        else

        nod2+=30;

 }

 nod2+=d2.dd;

nody=(yy-d2.yy)*365;

 for(i=d2.yy;i<yy;i++)

 if((i%4)==0)

 lc++;

 int y4=yy-d2.yy;

 while(y4>400)

 {

 lc++;

 y4-=400;

 }

 if((mm>2) && (yy%4)==0)

 lc++;

 if((d2.mm>2) && (d2.yy%4)==0)

 lc--;

 no_of_days=nody+nod1-nod2+lc;

 if(no_of_days>0)

 {

 cout<<"total number of days between these dates is=";

 return(no_of_days);

 }

 else

 return(no_of_days);

}

/* operator overloaded function to find the new date when no. of days are added to a

particular date.*/

date date::operator +(int nd)

{

 date dd3;

 while(nd>365)

 {

 yy++;

 nd-=365;

 }

 while(nd>30)

 {

 if(mm==1||mm==3||mm==5||mm==7||mm==8||mm==10||mm==12)

 {

 nd-=31;

 mm++;

 }

 else if(mm==2)

 {

 nd-=28;

 mm++;

 }

 else

 {

 nd-=30;

 mm++;

 }

 if(mm>12)

 {

 yy++;

 mm=1;

 }

 }

 dd=dd+nd;

 if(dd>30)

 {

 if(mm==4||mm==6||mm==9||mm==11)

 {

 mm++;

 dd-=30;

 }

 else if(mm==2)

 {

 mm++;

 dd-=28;

 }

 else if(dd>31)

 {

 mm++;

 dd-=31;

 }

 if(mm>12)

 {

 yy++;

 mm=1;

 }

 }

 dd3.mm=mm;

 dd3.dd=dd;

 dd3.yy=yy;

 cout<<"new date is:";

 cout<<dd<<"-"<<mm<<"-"<<yy<<endl;

 return(dd3);

}

//main function

void main()

{

 int res,num;

 date dd1,dd2;

 BEGIN:

 dd1.getdate();

 dd2.getdate();

 res=dd1-dd2;

 if(res<0)

 {

 cout<<"\n the first date should be greater than the second date\n";

 cout<<"so enter the dates again\n";

 goto BEGIN;

 }

 cout<<res;

 cout<<"\n enter the no. of days to be added to the FIRST date:";

 cin>>num;

 dd2=dd1+num;

}

OUTPUT

RUN-1

enter a valid date(dd mm yy)

30 2 2004

wrong input!!!

enter the date again....

29 2 2004

enter a valid date(dd mm yy)

12 6 2003

total number of days between these dates is=262

enter the no. of days to be added to the FIRST date:

new date is:24-3-2004

Press any key to continue

RUN-2

enter a valid date(dd mm yy)

31 12 2004

enter a valid date(dd mm yy)

31 12 2005

 the first date should be greater than the second date

so enter the dates again

enter a valid date(dd mm yy)

31 12 2004

enter a valid date(dd mm yy)

31 12 2003

total number of days between these dates is=366

enter the no. of days to be added to the FIRST date:13

new date is:13-1-2005

Press any key to continue